36x^2+1=17

Solution for 36x^2+1=17 equation:

36x^2+1=17

We move all terms to the left:

36x^2+1-(17)=0

We add all the numbers together, and all the variables

36x^2-16=0

a = 36; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·36·(-16)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*36}=\frac{-48}{72}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*36}=\frac{48}{72}
=2/3
$